利用Python发邮件（扫邮利器）

这里不能用冒号么，好像星号也显示不出来。。。大家等我改好了再看吧 — 沈金辉 2013/11/10 16:45

代码用

包围即可

import smtplib\\
import time\\
from email.mime.text import MIMEText\\
mail_to=" xx@xx.com"(发送目标)\\
time.sleep(5)\\
def send_mail(to_list,sub,content):\\
mail_host="smtp.xx.com"（发送服务器）\\
mail_user=" ** "(自己的邮箱用户名)\\
mail_pass=" ** "（自己邮箱的密码）\\
mail_postfix=" ** .com"（服务器名）\\
me=mail_user+"<"+mail_user+"@"+mail_postfix+">"\\
msg = MIMEText(content)\\
msg['Subject'] = sub\\
msg['From'] = me\\
msg['To'] = to_list\\
try:\\
s = smtplib.SMTP()\\
s.connect(mail_host)\\
s.login(mail_user,mail_pass)\\
s.sendmail(me, to_list, msg.as_string())\\
s.close()\\
print '1'\\
return True\\
except Exception, e:\\
print '2'\\
print str(e)\\
return False\\
if __name__ == '__main__':\\
if send_mail(mail_to,"hello world","Hello World!"):\\
print "发送成功"\\
else:\\
print "发送失败"\\